A man 3

A man buys a box of fruits containing 286 fruits. Out of these, 1/2 are apples, and the rest are pears. 4/13 of the pears are rotten. He sells the good pears at rupees 4 1/11 each. How much money does he receive on selling the good pears?

Final Answer:

x =  405 Rp

Step-by-step explanation:

$$\begin{gathered} n=286 \\ a=n\cdot \frac{1}{2}=286\cdot \frac{1}{2}=\frac{286\cdot 1}{2}=\frac{286}{2}=143 \\ p=n-a=286-143=143 \\ r=\frac{4}{13}\cdot p=\frac{4}{13}\cdot 143=\frac{4\cdot 143}{13}=\frac{572}{13}=44 \\ P=p-r=143-44=99 \\ c=4\frac{1}{11}=4+\frac{1}{11}=\frac{4\cdot 11+1}{11}=\frac{44+1}{11}=\frac{45}{11}\doteq 4.0909\text{Rp} \\ x=c\cdot P=\frac{45}{11}\cdot 99=\frac{45\cdot 99}{11}=\frac{4455}{11}=405\text{Rp} \end{gathered}$$

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