Truncated cone 5

The height of a cone 7 cm and the length of side is 10 cm and the lower radius is 3cm. What could the possible answer for the upper radius of truncated cone?

Result

r1 =  10.141 cm

Solution:

$h=7 \ \text{cm} \ \\ s=10 \ \text{cm} \ \\ r_{2}=3 \ \text{cm} \ \\ x=\sqrt{ s^2-h^2 }=\sqrt{ 10^2-7^2 } \doteq \sqrt{ 51 } \ \text{cm} \doteq 7.1414 \ \text{cm} \ \\ r=r_{2}-x <0 \ \\ r_{1}=r_{2}+x=3+7.1414 \doteq 10.1414 \doteq 10.141 \ \text{cm}$

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