Equivalent equation

Which equation, when solved, results in a different value of x than the other three?

A. $-\frac{7}{8}x-\frac{3}{4}=20$
Negative 7/8 x minus three-fourths = 20

B. $\frac{3}{4}+\frac{7}{8}x=-20$
Three-fourths + 7/8 x = negative 20

C. $-7\frac{1}{8}x-3/4=20$
Negative 7 ( 1/8 ) x minus three-fourths = 20

D. $-\frac{7}{8}(-\frac{8}{7}x)-\frac{3}{4}=20(-\frac{8}{7})$
Negative 7/8 (Negative 8/7 ) x minus three-fourths = 20 (Negative 8/7 )

Correct answer:

w = D

Step-by-step explanation:

$$\begin{gathered} -7/8\cdot a-3/4=20 \\ 7a=-166 \\ a=\frac{-166}{7}=-23.71428571 \\ a=\frac{-166}{7}\doteq -23.714286 \\ 3/4+7/8\cdot b=-20 \\ 7b=-166 \\ b=\frac{-166}{7}=-23.71428571 \\ b=\frac{-166}{7}\doteq -23.714286 \\ -7\cdot 1/8\cdot c-3/4=20 \\ 7c=-166 \\ c=\frac{-166}{7}=-23.71428571 \\ c=\frac{-166}{7}\doteq -23.714286 \\ -7/8\cdot (-8/7\cdot d)-3/4=20\cdot (-8/7) \\ 56d=-1238 \\ d=\frac{-1238}{56}=-22.10714286 \\ d=\frac{-619}{28}\doteq -22.107143 \\ a=b=c \\ w=D \end{gathered}$$

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