# Equivalent equation

Which equation, when solved, results in a different value of x than the other three?

A.

Negative 7/8 x minus three-fourths = 20

B.

Three-fourths + 7/8 x = negative 20

C.

Negative 7 ( 1/8 ) x minus three-fourths = 20

D.

Negative 7/8 (Negative 8/7 ) x minus three-fourths = 20 (Negative 8/7 )

A.

$-{\displaystyle \frac{7}{8}}x-{\displaystyle \frac{3}{4}}=20$

Negative 7/8 x minus three-fourths = 20

B.

$\frac{3}{4}}+{\displaystyle \frac{7}{8}}x=-20$

Three-fourths + 7/8 x = negative 20

C.

$-7{\displaystyle \frac{1}{8}}x-3\mathrm{/}4=20$

Negative 7 ( 1/8 ) x minus three-fourths = 20

D.

$-{\displaystyle \frac{7}{8}}(-{\displaystyle \frac{8}{7}}x)-{\displaystyle \frac{3}{4}}=20(-{\displaystyle \frac{8}{7}})$

Negative 7/8 (Negative 8/7 ) x minus three-fourths = 20 (Negative 8/7 )

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