Equivalent equation

Which equation, when solved, results in a different value of x than the other three?

A. $-\frac{7}{8}x-\frac{3}{4}=20$
Negative 7/8 x minus three-fourths = 20

B. $\frac{3}{4}+\frac{7}{8}x=-20$
Three-fourths + 7/8 x = negative 20

C. $-7\frac{1}{8}x-3/4=20$
Negative 7 ( 1/8 ) x minus three-fourths = 20

D. $-\frac{7}{8}(-\frac{8}{7}x)-\frac{3}{4}=20(-\frac{8}{7})$
Negative 7/8 (Negative 8/7 ) x minus three-fourths = 20 (Negative 8/7 )

Your answer:

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