# Equivalent equation

Which equation, when solved, results in a different value of x than the other three?

A.
$-\frac{7}{8}x-\frac{3}{4}=20$

Negative 7/8 x minus three-fourths = 20

B.
$\frac{3}{4}+\frac{7}{8}x=-20$

Three-fourths + 7/8 x = negative 20

C.
$-7\frac{1}{8}x-3\mathrm{/}4=20$

Negative 7 ( 1/8 ) x minus three-fourths = 20

D.
$-\frac{7}{8}\left(-\frac{8}{7}x\right)-\frac{3}{4}=20\left(-\frac{8}{7}\right)$

Negative 7/8 (Negative 8/7 ) x minus three-fourths = 20 (Negative 8/7 )

Result

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