Motion

If you walk to the station at 6.2 km/h, you arrive 52 minutes after the train has left. If you cycle at 23 km/h, you arrive 51 minutes before departure.
How far is the train station?

Final Answer:

s =  14.5712 km

Step-by-step explanation:

v1=6.2 km/h v2=23 km/h t1 = (x + 52)/60  h t2 = (x  51)/60  h s = v1   t1 = v2   t2 v1( x+ 52 ) = v2( x  51 ) x=v2v1v1 52+v2 51=236.26.2 52+23 51=84747789.0119 min t2=(x51)/60=(89.011951)/600.6335 h  s = s1 = s2 s=v2 t2=23 0.633514.5712 km   Verifying Solution:  t1=(x+52)/60=(89.0119+52)/602.3502 h s1=v1 t1=6.2 2.350214.5712 km



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