Coffee

In stock are three kinds of branded coffee prices:

I. kind......205 Kc/kg
II. kind......274 Kc/kg
III. kind.....168 Kc/kg

Mixing these three species in the ratio 8:5:6 create a mixture. What will be the price of 100 grams of this mixture?


Result

x =  21.147 Kc

Solution:

m1=100 gkg=100/1000 kg=0.1 kg  r=8 205+5 274+6 1688+5+6=401819211.4737 Kc/kg  x=r m1=211.4737 0.120099521.147421.147 Kcm_{1}=100 \ g \rightarrow kg=100 / 1000 \ kg=0.1 \ kg \ \\ \ \\ r=\dfrac{ 8 \cdot \ 205+5 \cdot \ 274+6 \cdot \ 168 }{ 8+5+6 }=\dfrac{ 4018 }{ 19 } \doteq 211.4737 \ \text{Kc/kg} \ \\ \ \\ x=r \cdot \ m_{1}=211.4737 \cdot \ 0.1 \doteq \dfrac{ 2009 }{ 95 } \doteq 21.1474 \doteq 21.147 \ \text{Kc}



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