Three 43

Three brothers inherited a cash amount of 62,000 and they divided it among themselves in the ratio of 5:4:1. How much more is the largest share than the smallest share?

Result

x =  24800

Solution:

p=62000 a=p⋅ 55+4+1=62000⋅ 55+4+1=31000 b=p⋅ 45+4+1=62000⋅ 45+4+1=24800 c=p⋅ 15+4+1=62000⋅ 15+4+1=6200  x=a−c=31000−6200=24800p=62000 \ \\ a=p \cdot \ \dfrac{ 5 }{ 5+4+1 }=62000 \cdot \ \dfrac{ 5 }{ 5+4+1 }=31000 \ \\ b=p \cdot \ \dfrac{ 4 }{ 5+4+1 }=62000 \cdot \ \dfrac{ 4 }{ 5+4+1 }=24800 \ \\ c=p \cdot \ \dfrac{ 1 }{ 5+4+1 }=62000 \cdot \ \dfrac{ 1 }{ 5+4+1 }=6200 \ \\ \ \\ x=a-c=31000-6200=24800

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