Car travels 1/3 of the trip on the first day, second day 2/5 of the trip and left even 340 km for next days. How long is the trip?


x =  1275 km


x13x25x=340 x(11325)=340 x=34011325 x=1275 kmx-\dfrac{ 1}{ 3} x - \dfrac{ 2}{ 5} x = 340 \ \\ x(1 - \dfrac{ 1}{ 3} - \dfrac{ 2}{ 5}) = 340 \ \\ x = \dfrac{ 340} {1 - \dfrac{ 1}{ 3} - \dfrac{ 2}{ 5}} \ \\ x = 1275 \ \text{km}

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