Speed of car

The car went to a city that was 240 km away. If his speed increased by 8 km/h, it would reach the finish one hour earlier. Determine its original speed.

Correct result:

v =  40 km/h

Solution:

s=vt  240=vt 240=(v+8)(t1)  240=(v+8)(240/v1)  240v=(v+8)(240v)  240 v=(v+8) (240v) v2+8v1920=0  a=1;b=8;c=1920 D=b24ac=8241(1920)=7744 D>0  v1,2=b±D2a=8±77442 v1,2=8±882 v1,2=4±44 v1=40 v2=48   Factored form of the equation:  (v40)(v+48)=0  v>0  v=v1=40=40 km/h

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