# Circle chord

What is the length d of the chord circle of diameter 51 mm, if the distance from the center circle is 19 mm?

Result

x =  34.015 mm

#### Solution:

$D = 51 \ mm \ \\ t = 19 \ mm \ \\ \ \\ r = D/2 = 51/2 = \dfrac{ 51 }{ 2 } = 25.5 \ mm \ \\ \ \\ (x/2)^2 = r^2 - t^2 \ \\ \ \\ x = 2 \cdot \ \sqrt{ r^2-t^2 } = 2 \cdot \ \sqrt{ 25.5^2-19^2 } = \sqrt{ 1157 } \doteq 34.0147 = 34.015 \ \text{ mm }$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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