Circle chord

What is the length d of the chord circle of diameter 51 mm, if the distance from the center circle is 19 mm?

Result

x =  34.015 mm

Solution:

D=51 mm t=19 mm  r=D/2=51/2=512=25.5 mm  (x/2)2=r2−t2  x=2⋅ r2−t2=2⋅ 25.52−192=1157≐34.0147=34.015  mm D = 51 \ mm \ \\ t = 19 \ mm \ \\ \ \\ r = D/2 = 51/2 = \dfrac{ 51 }{ 2 } = 25.5 \ mm \ \\ \ \\ (x/2)^2 = r^2 - t^2 \ \\ \ \\ x = 2 \cdot \ \sqrt{ r^2-t^2 } = 2 \cdot \ \sqrt{ 25.5^2-19^2 } = \sqrt{ 1157 } \doteq 34.0147 = 34.015 \ \text{ mm }

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