A tank

A tank is 7/9 full of water. In the morning, 1/5 of the tank's contents is drawn, and in the evening, 1/3 of the tank's contents is drawn. What fraction of the tank still contains water?

Final Answer:

x =  11/45

Step-by-step explanation:

$$\begin{gathered} V_1=\frac{7}{9}\doteq 0.7778 \\ {V}_2=\frac{1}{5}=0.2 \\ {V}_3=\frac{1}{3}\doteq 0.3333 \\ x=V_1-V_2-V_3=\frac{7}{9}-\frac{1}{5}-\frac{1}{3}=\frac{35}{45}-\frac{9}{45}-\frac{15}{45}=\frac{35-9-15}{45}=\frac{11}{45}=0.2444 \end{gathered}$$

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