Two cars

Two cars started against each other at the same time to journey long 293 km. First car went 41 km/h and second 41 km/h.

What distance will be between this cars 20 minutes before meet?

Result

s =  27.3 km

Solution:

v=41+41=82 km/h s=293(293+206082)=206082=27.3  km v = 41 + 41 = 82 \ km/h \ \\ s = 293 - (293 + \dfrac{ 20}{60} \cdot 82) = \dfrac{ 20}{60} \cdot 82 = 27.3 \ \text { km }







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