Perimeter 66414

The perimeter of triangle ABC is 162 dm. The lengths of its sides are in the ratios a:b = 2:3 and a:c = 8:7. Determine the lengths of the sides of the triangle.

Correct answer:

a =  48 dm
b =  72 dm
c =  42 dm

Step-by-step explanation:

o=162 dm  o=a+b+c a=2/3 b a=8/7 c 162=a+b+c a=2/3 b a=8/7 c  a+b+c=162 3a2b=0 7a8c=0  Pivot:Row1Row3 7a8c=0 3a2b=0 a+b+c=162  Row273 Row1Row2 7a8c=0 2b+3.429c=0 a+b+c=162  Row371 Row1Row3 7a8c=0 2b+3.429c=0 b+2.143c=162  Row321 Row2Row3 7a8c=0 2b+3.429c=0 3.857c=162  c=3.85714286162=42 b=203.4285714285714c=203.42857143 42=72 a=70+8c=70+8 42=48  a=48 b=72 c=42



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