Octane value

I loaded 10L 95 octane gasoline and 5L 100 octane gasoline. What is the resulting octane value of the gasoline in the tank?

Correct result:

o =  96.7

Solution:

o=10⋅ 95+5⋅ 10010+5=2903=96.7o=\dfrac{ 10 \cdot \ 95 + 5 \cdot \ 100 }{ 10+5 }=\dfrac{ 290 }{ 3 }=96.7

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