Square root 2

If the square root of 3m² +22 and -x = 0, and x=7, what is m?

Correct answer:

m₁ =  3
m₂ =  -3

Step-by-step explanation:

$$\begin{gathered} x=7 \\ \sqrt{3m^2+22}-x=0 \\ \sqrt{3m^2+22}-7=0 \\ \sqrt{3m^2+22}=7 \\ 3m^2+22=7^2 \\ 3m^2+22=49 \\ 3m^2-27=0 \\ a=3;b=0;c=-27 \\ D=b^2-4ac=0^2-4\cdot 3\cdot (-27)=324 \\ D>0 \\ {m}_{1,2}={\displaystyle \frac{-b\pm \sqrt{D}}{2a}}={\displaystyle \frac{\pm \sqrt{324}}{6}} \\ {m}_{1,2}={\displaystyle \frac{\pm 18}{6}} \\ {m}_{1,2}=\pm 3 \\ {m}_1=3 \\ {m}_2=-3 \\ \text{ Factored form of the equation: } \\ 3(m-3)(m+3)=0 \\ {m}_1=3 \end{gathered}$$

Our quadratic equation calculator calculates it.

$m_2=(-3)=-3$

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Showing 1 comment:

Night Fury

Thank u for your help☺️

7 months ago  Like

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