Three-digit digit sum

How many three-digit numbers have a digit sum of 6?
Write the ratio of the number of created even and odd numbers and adjust it to the basic form.

Final Answer:

n =  21
r =  4:3

Step-by-step explanation:

n1 = 105    N1 n2 = 114    P1 n3 = 123    N2 n4 = 132    P2 n5 = 141    N3 n6 = 150    P3 n7 = 204    P4 n8 = 213    N4 n9 = 222    P5 n10 = 231    N5 n11 = 240    P6 n12 = 303    N6 n13 = 312    P7 n14 = 321    N7 n15 = 330    P8 n16 = 402    P9 n17 = 411    N8 n18 = 420    P10 n19 = 501    N9 n20 = 510    P11 n21 = 600    P12  n=21
r=912=34=1311.3333=4:3



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