Variations 70724

If we increase the number of elements by 2, the number of variations of the second class without repetition increases by 22. How many elements do we have initially?

Correct answer:

n =  12

Step-by-step explanation:

V(n+2,2) = 22 + V(n,2)  (n+2)(n1) = 22 + n (n1)  2n24=0  2 n24=0  2n=24  n=224=12  n=12   Verifying Solution:  c1=(n+2) (n1)=(12+2) (121)=154 c2=n (n1)=12 (121)=132



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