Odd/even number

Pick any number. If that number is even, divide it by 2. If it's odd, multiply it by 3 and add 1. Now repeat the process with your new number. If you keep going, you'll eventually end up at 1. Every time. Prove. ..

Correct result:

x =  1

Solution:

n=12  n1=12/2=6 n2=6/2=3 n3=3 3+1=10 n4=10/2=5 n5=3 5+1=16 n6=16/2=8 n7=8/2=4 n8=4/2=2 n9=2/2=1 x=1n=12 \ \\ \ \\ n_{1}=12/2=6 \ \\ n_{2}=6/2=3 \ \\ n_{3}=3 \cdot \ 3+1=10 \ \\ n_{4}=10/2=5 \ \\ n_{5}=3 \cdot \ 5+1=16 \ \\ n_{6}=16/2=8 \ \\ n_{7}=8/2=4 \ \\ n_{8}=4/2=2 \ \\ n_{9}=2/2=1 \ \\ x=1



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Showing 2 comments:
#
Dr Math
always convergent to x = 1

see - https://en.wikipedia.org/wiki/Collatz_conjecture

he conjecture is named after Lothar Collatz, who introduced the idea in 1937, two years after receiving his doctorate. It is also known as the 3n + 1 conjecture, the Ulam conjecture (after Stanisław Ulam), Kakutani's problem (after Shizuo Kakutani), the Thwaites conjecture (after Sir Bryan Thwaites), Hasse's algorithm (after Helmut Hasse), or the Syracuse problem; the sequence of numbers involved is referred to as the hailstone sequence or hailstone numbers (because the values are usually subject to multiple descents and ascents like hailstones in a cloud), or as wondrous numbers.

#
Math student
it doesnt work

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