Aircraft

The plane flies at altitude 6500 m. At the time of first measurement was to see the elevation angle of 21° and second measurement of the elevation angle of 46°.

Calculate the distance the plane flew between the two measurements.

Correct result:

x =  10656.1 m

Solution:

$x=x_1-x_2=6500\cdot ({\displaystyle \frac{1}{\tan 21^{\circ }}}-{\displaystyle \frac{1}{\tan 46^{\circ }}})=10656.1\text{ m}$

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