Aircraft

The plane flies at altitude 6500 m. At the time of first measurement was to see the elevation angle of 21° and second measurement of the elevation angle of 46°.

Calculate the distance the plane flew between the two measurements.

Result

x =  10656.1 m

Solution:

x=x1−x2=6500⋅(1tan⁡21∘−1tan⁡46∘)=10656.1  m x = x_1 - x_2 = 6500 \cdot ( \dfrac{1}{ \tan 21 ^\circ } - \dfrac{1}{ \tan 46 ^\circ } ) = 10656.1 \ \text{ m }

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