The plane flies at altitude 6300 m. At the time of the first measurement was to see the elevation angle of 21° and the second measurement of the elevation angle of 46°.

Calculate the distance the plane flew between the two measurements.

Correct answer:

x =  10328.2 m

Step-by-step explanation:

h=6300 m α=21  β=46   tan α = h:x1 tan β = h:x1  x1=h/tanα=h/tan21° =6300/tan21° =6300/0.383864=16412.06111 m x2=h/tanβ=h/tan46° =6300/tan46° =6300/1.03553=6083.83928 m  x=x1x2=16412.06116083.8393=10328.2 m

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