Binibini

Binibini owns a triangular residential lot bounded by two roads intersecting at 70°. The sides of the lot along the road are 62 m and 43 m, respectively. Find the length of the fence needed to enclose the lot. (express answers to the nearest hundredths)

Final Answer:

o =  167.2 m

Step-by-step explanation:

$$\begin{gathered} a=62\text{m} \\ b=43\text{m} \\ \gamma =70{}^{\circ } \\ a-\gamma -b \\ {c}^2=a^2+b^2-2\cdot a\cdot b\cdot \cos \gamma \\ c=\sqrt{a^2+b^2-2\cdot a\cdot b\cdot \cos \gamma }=\sqrt{a^2+b^2-2\cdot a\cdot b\cdot \cos 70°}=\sqrt{62^2+43^2-2\cdot 62\cdot 43\cdot \cos 70°}=\sqrt{62^2+43^2-2\cdot 62\cdot 43\cdot 0.34202}=62.20409\text{m} \\ o=a+b+c=62+43+62.2041=167.2\text{m} \end{gathered}$$

Try calculation via our triangle calculator.

Try another example