Express train

International express train drove from Kosice to Teplice. In the first 279 km, the track was repaired, and therefore it was moving at a speed of 10km/h less than it was scheduled to drive. The rest of the 465 km trip has increased the speed by 8 km/h than the timetable speed. It came to Teplice for a while. Find the average speed of the train to drive according to the timetable.

Correct result:

v =  64 km/h

Solution:

t1+t2=t  279v10+465v+8=279+465v   279(v+8)v+465 (v10) v=(279+465)(v+8) (v10)  279 (v+8) v+465 (v10) v=(279+465) (v+8) (v10)  930v=59520  v=64=64 km/h



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