Acceleration 7487

The runway of the aircraft on the mother ship is 49m long. Calculate the aircraft's acceleration so that its speed when leaving the ejection device reaches 252km/h.

Final Answer:

a =  50 m/s²

Step-by-step explanation:

$$\begin{gathered} s=49\text{m} \\ v=252\text{km/h}\to \text{m/s}=252:3.6\text{m/s}=70\text{m/s} \\ s=\frac{1}{2}a{t}^2 \\ v=at \\ 2s=vt \\ t=2\cdot s/v=2\cdot 49/70=\frac{7}{5}=1.4\text{s} \\ a=v/t=70/1.4=50{\text{m/s}}^2 \end{gathered}$$

Try another example