Starting

The aircraft has a take-off speed of 310 km/h, a take-off weight of 16.5 t, and is taking off on a 2 km take-off runway. The flight speed is 880hm/h, the flight altitude is 10 km.
a) Determine the acceleration of the aircraft during takeoff and the takeoff time.
b) Determine the thrust of the engines
c) On what shortest path is the cruising speed and altitude achieved at thrust F?

Correct answer:

a =  1.8538 m/s²
t =  46.4516 s
F =  30587.3843 N
s₃ =  16116.5453 m

Step-by-step explanation:

$F=m\cdot a=16500\cdot 1.8538=30587.3843\text{N}$

$$\begin{gathered} v=a\cdot t_3 \\ {t}_3=v/a=244.4444/1.8538\doteq 131.8626\text{s} \\ {s}_3=\frac{1}{2}\cdot a\cdot t_3^2=\frac{1}{2}\cdot 1.8538\cdot 131.8626^2=16116.5453\text{m} \end{gathered}$$

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