Javelin

Danilo threw his javelin over a distance of 10 5/16 meters. Mark threw his javelin over a distance of 7 7/8 meters. How much farther did one javelin travel than the other?

Final Answer:

x =  2 ⁷⁄₁₆ = 39/16 m

Step-by-step explanation:

$$\begin{gathered} a=10\frac{5}{16}=10+\frac{5}{16}=\frac{10\cdot 16+5}{16}=\frac{160+5}{16}=\frac{165}{16}=10.3125\text{m} \\ b=7\frac{7}{8}=7+\frac{7}{8}=\frac{7\cdot 8+7}{8}=\frac{56+7}{8}=\frac{63}{8}=7.875\text{m} \\ x=a-b=\frac{165}{16}-\frac{63}{8}=\frac{165}{16}-\frac{126}{16}=\frac{165-126}{16}=\frac{39}{16}=\frac{39}{16}\text{m}=2\frac{7}{16}\text{m}=2.4375\text{m} \end{gathered}$$

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