In January, 2 liters of lemonade were sold for CZK 24, while in February, 2.5 liters of lemonade sold at same price. How much percent was 1 liter of lemonade cheaper in February than in January?

Result

p =  20 %

#### Solution:

$c_{ 1 } = 24/2 = 12 \ Kc/l \ \\ c_{ 2 } = 24/2.5 = \dfrac{ 48 }{ 5 } = 9.6 \ Kc/l \ \\ p = 100 \cdot \ \dfrac{ c_{ 1 }-c_{ 2 } }{ c_{ 1 } } = 100 \cdot \ \dfrac{ 12-9.6 }{ 12 } = 20 = 20 \%$

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