Closed drum

Find the total surface area of a closed cylindrical drum if it's diameter is 50 cm and height is 45 cm . (π= 3.14)

Result

S =  10995.574 cm2

Solution:

D=50 cm h=45 cm  r=D/2=50/2=25 cm S1=π⋅ r2=3.1416⋅ 252≐1963.4954 cm2 S2=π⋅ D⋅ h=3.1416⋅ 50⋅ 45≐7068.5835 cm2  S=2⋅ S1+S2=2⋅ 1963.4954+7068.5835≐10995.5743=10995.574 cm2D = 50 \ cm \ \\ h = 45 \ cm \ \\ \ \\ r = D/2 = 50/2 = 25 \ cm \ \\ S_{ 1 } = \pi \cdot \ r ^2 = 3.1416 \cdot \ 25 ^2 \doteq 1963.4954 \ cm^2 \ \\ S_{ 2 } = \pi \cdot \ D \cdot \ h = 3.1416 \cdot \ 50 \cdot \ 45 \doteq 7068.5835 \ cm^2 \ \\ \ \\ S = 2 \cdot \ S_{ 1 } + S_{ 2 } = 2 \cdot \ 1963.4954 + 7068.5835 \doteq 10995.5743 = 10995.574 \ cm^2

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