An archer

An archer stands 60 meters (m) from a target. She launches an arrow that lands 3 centimeters (cm) from the bull's eye. The archer changes her position to 40 m from the target, and her next arrow lands 2 cm from the bull's eye. She changes her position to 20 m, and her next arrow lands 1 cm from the bull's eye.

Which points describe the situation when the archer stands at 40 m?

Let the x-coordinate be the archer's distance from the target in meters, and let the y-coordinate be the arrow's distance from the bull's eye in centimeters.

Final Answer:

e : e=x^2/600-x/2+4/3=y

Step-by-step explanation:




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Showing 1 comment:
Math student
It's really hard

3 years ago  1 Like




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