Dimensions 8044

In the given rectangle, the length is 12 m greater than the width. We get a square if we reduce the length by 10 m and increase the width by 2 m. The area of the original rectangle is 300 m2 more than the area of the square. Determine the dimensions of the rectangle.

Correct answer:

a =  50 m
b =  38 m

Step-by-step explanation:

a = 12 + b a10 = 2+b  a b = (a10) (2+b) + 300   a (a12) = (a10) (2+(a12)) + 300  8a=400  8 a=400  8a=400  a=8400=50  a=50=50 m
b=a12=5012=38=38 m  S1=a b=50 38=1900 m2 S2=(a10) (2+b)=(5010) (2+38)=1600 m2  S3=S1S2=19001600=300 m2

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