Trapezoid cross section

Calculate how many hectoliters of water can fit in a fifty-meter sloped pool; if the smallest depth is 1.2 m and the largest depth is 3 m, the width of the pool is 20 m.

Final Answer:

V =  21000 hl
n =  13067

Step-by-step explanation:

h1​=1.2 m h2​=3 m a=20 m b=50 m  c=2h1​+h2​​=21.2+3​=1021​=2.1 m V1​=a⋅ b⋅ c=20⋅ 50⋅ 2.1=2100 m3  V=V1​→ hl=V1​⋅ 10  hl=2100⋅ 10  hl=21000 hl=21000 hl
x=15 cm→ m=15:100  m=0.15 m S=h1​⋅ a+h2​⋅ a+2⋅ c⋅ b=1.2⋅ 20+3⋅ 20+2⋅ 2.1⋅ 50=294 m2 S1​=x2=0.152=4009​=0.0225 m2  n=S/S1​=294/0.0225=13067

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solid geometryplanimetricsUnits of physical quantitiesGrade of the word problem

 
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