Kerosene pressure difference

Kerosene (ρ1 = 830 kg . m-3) flows through the pipe. Calculate the pressure difference in the given sections when the mercury level difference (ρ2 = 13600 kg . m-3) in the mercury differential manometer is h = 2.2 dm.

Final Answer:

Δ =   Pa

Step-by-step explanation:

$$\begin{gathered} {\rho }_1=830{\text{kg/m}}^3 \\ {\rho }_2=13600{\text{kg/m}}^3 \\ {h}_2=2.2\text{dm}\to \text{m}=2.2:10\text{m}=0.22\text{m} \\ g=9.81{\text{m/s}}^2 \\ \Delta ={\Delta }_2={\rho }_2\cdot g\cdot h_2=13600\cdot 9.81\cdot 0.22=29351.52\text{Pa}=\text{Pa} \end{gathered}$$

Try another example