The factory 3

The factory is 18 km away from the city. A cyclist leaves the factory for the city, and half an hour after him from the same place, a motorcyclist arrives 6 minutes before the cyclist in the city. Find the speed of each, knowing that the speed of the cyclist is two times smaller than that of the motorcyclist.

Correct answer:

v1 =  15 km/h
v2 =  30 km/h

Step-by-step explanation:

s=18 km t1=1/2=21=0.5 h t2=6 min h=6:60  h=0.1 h Δ=t1+t2=0.5+0.1=53=0.6 h  s=s1=s2 s = v1 t s = v2 (tΔ) v1 = v2/2  s = v1 t s = 2 v1 (tΔ)  s = 2 v1 (s/v1Δ)  v1 s = 2 v1 (sΔ v1)  s=2(sΔ v1) 18=2(180.6 v1)  18=2 (180.6 v1)  1.2v1=18  v1=1.218=15  v1=15=15 km/h
v2=2 v1=2 15=30=30 km/h   Verifying Solution:  T1=s/v1=18/15=56=1.2 h T2=T1Δ=1.20.6=53=0.6 h  s1=v1 T1=15 1.2=18 km s2=v2 T2=30 0.6=18 km s1=s2=s

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