Hexagon

There is regular hexagon ABCDEF. If area of the triangle ABC is 22, what is area of the hexagon ABCDEF?

I do not know how to solve it simply....

Correct result:

S =  132

Solution:

S(ΔABC)=S(ΔABS) S=6SABS=6SABC=622=132S(\Delta ABC) = S(\Delta ABS) \ \\ S = 6 S_{ABS} = 6 S_{ABC} = 6 \cdot 22 = 132



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