Camel and water

84% of the camel's weight is water. After drinking, its weight increased to 832 kg, and water accounted for 85% of its weight. How much did it weigh before drinking?

Final Answer:

m =  780 kg

Step-by-step explanation:


0.84 m = w
0.85 (m+x) = w+x
m+x = 832


0.84·m = w
0.85·(m+x) = w+x
m+x = 832

0.84m-w = 0
0.85m-w-0.15x = 0
m+x = 832

Pivot: Row 1 ↔ Row 3
m+x = 832
0.85m-w-0.15x = 0
0.84m-w = 0

Row 2 - 0.85 · Row 1 → Row 2
m+x = 832
-w-x = -707.2
0.84m-w = 0

Row 3 - 0.84 · Row 1 → Row 3
m+x = 832
-w-x = -707.2
-w-0.84x = -698.88

Row 3 - Row 2 → Row 3
m+x = 832
-w-x = -707.2
0.16x = 8.32


x = 8.32/0.16 = 52
w = -707.2+x/-1 = -707.2+52/-1 = 655.2
m = 832-x = 832-52 = 780

m = 780
w = 3276/5 = 655.2
x = 52

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You need to know the following knowledge to solve this word math problem:

algebrabasic operations and conceptsUnits of physical quantitiesGrade of the word problem

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