Camel and water

84% of the camel's weight is water. After drinking, its weight increased to 832 kg, and water accounted for 85% of its weight. How much did it weigh before drinking?

Final Answer:

m =  780 kg

Step-by-step explanation:

r1​=84%=10084​=2521​=0.84 r2​=85%=10085​=2017​=0.85 m1​=832 kg  r1​ ⋅  m = w r2​ (m+x) = w+x m+x = m1​   r2​ (m+x) = r1​ ⋅  m + x  m+x = m1​  r2​ (m+(m1​−m)) = r1​ ⋅  m + (m1​−m) r2​ ⋅  m1​ = r1​ ⋅  m + m1​−m  m =  r1​ −1r2​⋅ m1​ − m1​​ m=m1​⋅ 1−r1​1−r2​​=832⋅ 1−0.841−0.85​=780 kg x=m1​−m=832−780=52 kg w=r1​⋅ m=0.84⋅ 780=53276​=655.2 kg

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You need to know the following knowledge to solve this word math problem:

algebrabasic operations and conceptsUnits of physical quantitiesGrade of the word problem

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