Bomber

A bomber flies at altitude 10 km at a speed of 850 km/h. At what horizontal distance from the target must the pilot release the bomb to hit the target?

Ignore air resistance and use gravitational acceleration g = 9.81 m/s².

Final Answer:

s =  10661 m

Step-by-step explanation:

$$\begin{gathered} h=10\text{km}\to \text{m}=10\cdot 1000\text{m}=10000\text{m} \\ v=850\text{km/h}\to \text{m/s}=850:3.6\text{m/s}=236.11111\text{m/s} \\ g=9.81{\text{m/s}}^2 \\ h=\frac{1}{2}\cdot g\cdot t^2 \\ t=\sqrt{\frac{2\cdot h}{g}}=\sqrt{\frac{2\cdot 10000}{9.81}}\doteq 45.1524\text{s} \\ s=v\cdot t=236.1111\cdot 45.1524=10661\text{m} \end{gathered}$$

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