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Calculate how many g's (gravity accelerations) feel glider pilot when turning the horizontal circles of radius 148 m flying at 95 km/h. Centripetal acceleration is proportional to the square of the speed and inversely proportional to the radius of rotation.

Consider a vertically acting gravity acceleration g=9.81 ms-1.

Result

x =  1.11 g

Solution:

 aC=v2r=4.705 m/s2 x=ag a2=g2+aC2 x=g2+aC2g x=9.812+(26.3892148)29.81  x=1.11  g  \ \\ a_C = \dfrac{ v^2 }{ r} = 4.705 \ m/s^2 \ \\ x = \dfrac{a}{g} \ \\ a^2 = g^2 + a_C^2 \ \\ x = \dfrac{ \sqrt{ g^2 + a_C^2 }}{ g } \ \\ x = \dfrac{ \sqrt{ 9.81^2 + (\dfrac{ 26.389^2 }{ 148 })^2 }}{ 9.81 } \ \\ \ \\ x = 1.11 \ \text{ g }



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