# Free fall

Lloyd fall from height 7 m. Calculate the speed he hit the ground when falling with acceleration g = 9.81 m/s2

Correct result:

v =  42.19 km/h

#### Solution:

$v = 9.81\cdot \sqrt{ \dfrac{ 2\cdot 7}{ 9.81}} \cdot 3.6 = \sqrt{ 2\cdot 7 \cdot 9.81} \cdot 3.6 = 42.19 \ \text{km/h}$

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