Motion2

A cyclist left town at 24 km/h. A car set off 0.5 hours later in the same direction and caught up with the cyclist in 58 minutes. How fast did the car travel, and how far from the town did it catch the cyclist?

Final Answer:

v2 =  36.4 km/h
s =  35.2 km

Step-by-step explanation:

v1=24 km/h t1=0.5 h t2=58 min h=58:60  h=0.96667 h  t=t1+t2=0.5+0.9667=15221.4667 h  s1=s2 v1 t = v2 t2  v2=v1 t2t=24 0.96671.4667=36.4 km/h
s=v1 t=24 1.4667=35.2 km



Help us improve! If you spot a mistake, please let let us know. Thank you!







Tips for related online calculators
Do you have a linear equation or system of equations and are looking for a solution? Or do you have a quadratic equation?
Do you want to convert length units?
Do you want to convert velocity (speed) units?
Do you want to round the number?
Do you want to convert time units like minutes to seconds?

You need to know the following knowledge to solve this word math problem:

algebraarithmeticbasic operations and conceptsnumbersUnits of physical quantitiesthemes, topicsGrade of the word problem

Related math problems and questions: