Determine 10561

The hollow nickel ball has an outer diameter of 0.4 meters and an inner diameter of 0.3 meters. Determine its weight if the nickel density is 9000 kg/m3.

Correct answer:

m =  174.3584 kg

Step-by-step explanation:

D1=0.4 m D2=0.3 m  h=9000 kg/m3  r1=D1/2=0.4/2=51=0.2 m r2=D2/2=0.3/2=203=0.15 m  V1=34 π r13=34 π 513=34 3.1416 0.230.0335 m3 V2=34 π r23=34 π 2033=34 3.1416 0.1530.0141 m3  V=V1V2=0.03350.01410.0194 m3  m=h V=9000 V=9000 0.0194=174.3584 kg

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