Wall thickness

The hollow metal ball has an outside diameter of 40 cm. Determine the wall thickness if the weight is 25 kg and the metal density is 8.45 g/cm3.

Correct result:

h =  0.6068 cm

Solution:

D=40 cm R=D/2=40/2=20 cm  m=25 kg g=25 1000  g=25000 g ρ=8.45 g/cm3  m=ρV V=m/ρ=25000/8.452958.5799 cm3  V=V1V2 V=43 π R343 π (Rh)3 3 V4πR3=(Rh)3  Rh=R33 V4π3 h=RR33 V4π3=202033 2958.57994 3.14163=0.6068 cm



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