Wall thickness

The hollow metal ball has an outside diameter of 40 cm. Determine the wall thickness if the weight is 25 kg and the metal density is 8.45 g/cm3.

Correct answer:

h =  0.6068 cm

Step-by-step explanation:

D=40 cm R=D/2=40/2=20 cm  m=25 kg g=25 1000  g=25000 g ρ=8.45 g/cm3  m = ρ V V=m/ρ=25000/ρ2958.5799 cm3  V = V1V2 V = 34 π R334 π (Rh)3 4π3 V  R3 = (Rh)3  Rh = (R3  4π3 V) 1/3 h=R3R34π3 V=2032034 3.14163 2958.5799=0.6068 cm

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