Wall thickness

The hollow metal ball has an outside diameter of 40 cm. Determine the wall thickness if the weight is 25 kg and the metal density is 8.45 g/cm3.

Correct result:

h =  0.6068 cm

Solution:

D=40 cm R=D/2=40/2=20 cm  m=25 kg→ g=25⋅ 1000  g=25000 g ρ=8.45 g/cm3  m=ρV V=m/ρ=25000/8.45≐2958.5799 cm3  V=V1−V2 V=43⋅ π⋅ R3−43⋅ π⋅ (R−h)3 3⋅ V4π−R3=−(R−h)3  R−h=R3−3⋅ V4π3 h=R−R3−3⋅ V4π3=20−203−3⋅ 2958.57994⋅ 3.14163=0.6068 cm

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