Hollow sphere

Calculate the weight of a hollow dural sphere (density 2.75 g/cm3) if the inner diameter is 18 cm and the wall thickness is 3 mm.

Correct answer:

m =  868.1 g

Step-by-step explanation:

ρ=2.75 g/cm3 D=18 mm h=3 mm cm=3:10  cm=0.3 cm  r1=D/2+h=18/2+0.3=1093=9.3 cm r2=D/2=18/2=9 cm  V1=34 π r13=34 3.1416 9.333369.2827 cm3 V2=34 π r23=34 3.1416 933053.6281 cm3  V=V1V2=3369.28273053.6281315.6547 cm3  m=ρ V=2.75 315.6547=868.1 g



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