# Hollow sphere

Calculate the weight of a hollow tungsten sphere (density 19.3 g/cm3), if the inner diameter is 14 cm and wall thickness is 3 mm.

Result

m =  3720.2 g

#### Solution:

$\ \\ m = \rho( V_1 - V_2 ) \ \\ m = \dfrac{ 19.3 \cdot 4}{3}\pi \left({\dfrac{ (14+3/5)}{2}}^3-{\dfrac{ 14}{2}}^3\right) = 3720.2 \ \text{ g }$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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