Hollow sphere

Calculate the weight of a hollow stříbrné sphere (density 10.5 g/cm3) if the vnitřní diameter is 15 cm and wall thickness is 1 mm.

Correct result:

m =  752.1 g

Solution:

ρ=10.5 g/cm3 D=15 mm h=1 mm→ cm=1/10  cm=0.1 cm  r1=D/2+h=15/2+0.1=385=7.6 cm r2=D/2=15/2=152=7.5 cm  V1=43⋅ π⋅ r13=43⋅ 3.1416⋅ 7.63≐1838.7784 cm3 V2=43⋅ π⋅ r23=43⋅ 3.1416⋅ 7.53≐1767.1459 cm3  V=V1−V2=1838.7784−1767.1459≐71.6325 cm3  m=ρ⋅ V=10.5⋅ 71.6325=752.1 g

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