Hollow sphere

Calculate the weight of a hollow tungsten sphere (density 19.3 g/cm3), if the inner diameter is 14 cm and wall thickness is 3 mm.

Result

m =  3720.2 g

Solution:

 m=ρ(V1−V2) m=19.3⋅43π((14+3/5)23−1423)=3720.2  g  \ \\ m = \rho( V_1 - V_2 ) \ \\ m = \dfrac{ 19.3 \cdot 4}{3}\pi \left({\dfrac{ (14+3/5)}{2}}^3-{\dfrac{ 14}{2}}^3\right) = 3720.2 \ \text{ g }

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