RT 10

Area of right triangle is 84 cm2 and one of its cathethus is a=10 cm. Calculate perimeter of the triangle ABC.

Correct result:

x =  46.35 cm

Solution:

x=a+b+c  a=10 cm S=84 cm2 S=ab/2  b=2S/a=284/10=16.8 cm  c2=a2+b2 c=a2+b2=102+16.82=19.55 cm  x=a+b+c=46.35 cm

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