# Racer

The first racer run at a speed 20 m/s and is 750 meters before the finish and ahead 79 meters before second competitor.

At what speed must run the second racer to catch first racer at the finish line?

Result

v2 =  22.11 m/s

#### Solution:

$t_1 = t_2 \ \\ s_1 = 750 = v_1 t_1 \ \\ t_1 = 750/ 20 = 37.5\ s \ \\ \ \\ v_2 = \dfrac{ s_1 + s_2 }{ t_2 } \ \\ v_2 =v_1 \cdot \dfrac{ s_1 + s_2 }{ s_1 } \ \\ v_2 = \dfrac{ 750 + 79 }{ 37.5 } = 22.11 \ \text{ m/s }$

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