Year 2020

The four-digit number divided by 2020 gives a result of 1, **. (Can not be in form 1,*0. ) Write all the options.

Result

n1 =  2323
n2 =  2525
n3 =  2727
n4 =  2929
n5 =  3131
n6 =  3333
n7 =  3535
n8 =  3737
n9 =  3939

Solution:

n1=2323 d1=n1/2020=2323/2020=2320=1.15n_{ 1 } = 2323 \ \\ d_{ 1 } = n_{ 1 }/2020 = 2323/2020 = \dfrac{ 23 }{ 20 } = 1.15
n2=2525 d2=n2/2020=2525/2020=54=1.25n_{ 2 } = 2525 \ \\ d_{ 2 } = n_{ 2 }/2020 = 2525/2020 = \dfrac{ 5 }{ 4 } = 1.25
n3=2727 d3=n3/2020=2727/2020=2720=1.35n_{ 3 } = 2727 \ \\ d_{ 3 } = n_{ 3 }/2020 = 2727/2020 = \dfrac{ 27 }{ 20 } = 1.35
n4=2929 d4=n4/2020=2929/2020=2920=1.45n_{ 4 } = 2929 \ \\ d_{ 4 } = n_{ 4 }/2020 = 2929/2020 = \dfrac{ 29 }{ 20 } = 1.45
n5=3131 d5=n5/2020=3131/2020=3120=1.55n_{ 5 } = 3131 \ \\ d_{ 5 } = n_{ 5 }/2020 = 3131/2020 = \dfrac{ 31 }{ 20 } = 1.55
n6=3333 d6=n6/2020=3333/2020=3320=1.65n_{ 6 } = 3333 \ \\ d_{ 6 } = n_{ 6 }/2020 = 3333/2020 = \dfrac{ 33 }{ 20 } = 1.65
n7=3535 d7=n7/2020=3535/2020=74=1.75n_{ 7 } = 3535 \ \\ d_{ 7 } = n_{ 7 }/2020 = 3535/2020 = \dfrac{ 7 }{ 4 } = 1.75
n8=3737 d8=n8/2020=3737/2020=3720=1.85n_{ 8 } = 3737 \ \\ d_{ 8 } = n_{ 8 }/2020 = 3737/2020 = \dfrac{ 37 }{ 20 } = 1.85
n9=3939 d9=n9/2020=3939/2020=3920=1.95n_{ 9 } = 3939 \ \\ d_{ 9 } = n_{ 9 }/2020 = 3939/2020 = \dfrac{ 39 }{ 20 } = 1.95







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