EQL triangle

Correct result:

r1 =  22.2 cm
r2 =  44.5 cm

Solution:

$\ \\ \tan 30 ^\circ = \dfrac{ r_1 }{ \dfrac{ 77}{2 } } \ \\ r_1= \dfrac{ 77}{2 } \tan 30 ^\circ = 22.2 \ \text{cm}$
$\ \\ \cos 30 ^\circ = \dfrac{ \dfrac{ 77}{2 } }{ r_2 } \ \\ r_2= \dfrac{ 77}{2 } / \cos 30 ^\circ = 44.5 \ \text{cm}$

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