ISO trapezium

Calculate area of isosceles trapezoid with base 95 long, leg 27 long and with the angle between the base and leg 70 degrees.

Result

S =  2176.02

Solution:

a=95 v=27⋅sin⁡70∘=25.37 c=a−2acos⁡70∘=30.02  S=a+c2v=95+30.022⋅25.37=2176.02a = 95 \ \\ v = 27 \cdot \sin 70 ^\circ = 25.37 \ \\ c = a-2a \cos 70 ^\circ = 30.02 \ \\ \ \\ S = \dfrac{a+c}{2} v = \dfrac{ 95+30.02 }{2} \cdot 25.37 = 2176.02

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