RRL Basics

What is the length of the smaller base and the height of an isosceles trapezoid if a = 9 dm, the leg is 6 dm, and angle ACB = 90°?

Final Answer:

c =  1 dm
h =  4.4721 dm

Step-by-step explanation:

a=9 dm r=6 dm ACB=90   AC=a2r2=9262=3 5 dm6.7082 dm  S1=2r AC=26 6.7082=9 5 dm220.1246 dm2  S1 = 2a h  h=a2 S1=92 20.1246=2 5 dm4.4721 dm  x=r2h2=624.47212=4 dm  a = x+c+x  c=a2 x=92 4=1 dm



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