Coordinates of square vertices

I have coordinates of square vertices A / -3; 1/and B/1; 4 /. Find coordinates of vertices C and D, C 'and D'. Thanks Peter.

Correct result:

x2 =  2.9696
y2 =  -0.5957
x3 =  -1.0304
y3 =  -3.5957
x4 =  -0.9696
y4 =  8.5957
x5 =  -4.9696
y5 =  5.5957

Solution:

x0=3 y0=1  x1=1 y1=4  a=(x0x1)2+(y0y1)2=((3)1)2+(14)2=5  tanα=y0y1x0y1=14(3)4=370.4286  α=arctan(y0y1x0y1)=arctan(14(3)4)0.4049 rad  dx=a cos(α)=5 cos(0.4049)4.5957 dy=a sin(α)=5 sin(0.4049)1.9696  x2=x1+dy=1+1.9696=2.9696
y2=y1dx=44.5957=0.5957
x3=x0+dy=(3)+1.9696=1.0304
y3=y0dx=14.5957=3.5957
x4=x1dy=11.9696=0.9696
y4=y1+dx=4+4.5957=8.5957
x5=x0dy=(3)1.9696=4.9696
y5=y0+dx=1+4.59575.5957=5.5957  a2=(x0x3)2+(y0y3)2=((3)(1.0304))2+(1(3.5957))2=5 a3=(x1x2)2+(y1y2)2=(12.9696)2+(4(0.5957))2=5 a4=(x2x3)2+(y3y2)2=(2.9696(1.0304))2+((3.5957)(0.5957))2=5  b2=(x0x5)2+(y0y5)2=((3)(4.9696))2+(15.5957)2=5 b3=(x1x4)2+(y1y4)2=(1(0.9696))2+(48.5957)2=5 b4=(x4x5)2+(y4y5)2=((0.9696)(4.9696))2+(8.59575.5957)2=5



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Tips to related online calculators
For Basic calculations in analytic geometry is a helpful line slope calculator. From coordinates of two points in the plane it calculate slope, normal and parametric line equation(s), slope, directional angle, direction vector, the length of segment, intersections the coordinate axes etc.
Pythagorean theorem is the base for the right triangle calculator.
See also our trigonometric triangle calculator.

 
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