Coordinates of square vertices

The ABCD square has the center S [−3, −2] and the vertex A [1, −3]. Find the coordinates of the other vertices of the square.

Correct result:

x1 =  -7
y1 =  -1
x2 =  -2
y2 =  2
x3 =  -4
y3 =  -6

Solution:

s0=−3 s1=−2  x0=1 y0=−3  d0=x0−s0=1−(−3)=4 d1=y0−s1=(−3)−(−2)=−1  n⊥d ∣n∣=∣d∣ n.d=0  n0=−d1=−(−1)=1 n1=d0=4  x1=s0−d0=(−3)−4=−7
y1=s1−d1=(−2)−(−1)=−1
x2=s0+n0=(−3)+1=−2
y2=s1+n1=(−2)+4=2
x3=s0−n0=(−3)−1=−4
y3=s1−n1=(−2)−4=−6

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