# Crystal water

The chemist wanted to check the content of water of crystallization of chromic potassium alum K

How many crystal water instead of 24 molecules contain salt?

Additional data to compute:

M (K

M(K

_{2}SO_{4}* Cr_{2}(SO_{4}) 3 * 24 H_{2}O, which was a long time in the laboratory. From 96.8 g of K_{2}SO_{4}* Cr_{2}(SO_{4}) 3 * 24 H_{2}O prepared 979 cm^{3}solution of base. Subsequently, the 293 cm^{3}of the stock solution, a solution of barium nitrate, and a precipitate precipitated weighing 19.6 g.How many crystal water instead of 24 molecules contain salt?

Additional data to compute:

M (K

_{2}SO_{4}* Cr_{2}(SO_{4}) 3 * 24 H_{2}O) = 998.2 g / mol, M(BaSO_{4}) = 233.4 g / molM(K

_{2}SO_{4}* Cr_{2}(SO_{4}) 3) = 566.2 g / mol, M (H_{2}O) = 18 g / mol**Result****Leave us a comment of this math problem and its solution (i.e. if it is still somewhat unclear...):**

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