A square base

A solid right pyramid has a square base. The length of the base edge is 4 centimeters and the height of the pyramid is 3 centimeters. What is the volume of the pyramid?

Result

V =  16 cm3

Solution:

a=4 cm h=3 cm  S1=a2=42=16 cm2  V=13⋅ S1⋅ h=13⋅ 16⋅ 3=16=16 cm3a = 4 \ cm \ \\ h = 3 \ cm \ \\ \ \\ S_{ 1 } = a^2 = 4^2 = 16 \ cm^2 \ \\ \ \\ V = \dfrac{ 1 }{ 3 } \cdot \ S_{ 1 } \cdot \ h = \dfrac{ 1 }{ 3 } \cdot \ 16 \cdot \ 3 = 16 = 16 \ cm^3

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