The bridge

A vehicle weighing 5,800 kg passes 41 km/h on an arched bridge with a radius of curvature of 62 m. What force is pushing the car onto the bridge as it passes through the center? What is the maximum speed it can cross over the center of the bridge so that it does not fly off the road?

Result

F =  44764.139 N
v2 =  24.662 m/s

Solution:

m=5800 kg v1=41 km/h=41/3.6 m/s=11.38889 m/s r=62 m g=9.81 m/s2  F=FgFo F=m gm v12/r=5800 9.815800 11.38892/6244764.139 N44764.139 Nm=5800 \ \text{kg} \ \\ v_{1}=41 \ km/h=41 / 3.6 \ m/s=11.38889 \ m/s \ \\ r=62 \ \text{m} \ \\ g=9.81 \ \text{m/s}^2 \ \\ \ \\ F=F_g - F_o \ \\ F=m \cdot \ g - m \cdot \ v_{1}^2 / r=5800 \cdot \ 9.81 - 5800 \cdot \ 11.3889^2 / 62 \doteq 44764.139 \ \text{N} \doteq 44764.139 \ \text{N}
Fg=Fo m g=m v22/r g=v22/r  v2=r g=62 9.8124.662124.662 m/sF_g=F_o \ \\ m \cdot \ g=m \cdot \ v_{2}^2 / r \ \\ g=v_{2}^2 / r \ \\ \ \\ v_{2}=\sqrt{ r \cdot \ g }=\sqrt{ 62 \cdot \ 9.81 } \doteq 24.6621 \doteq 24.662 \ \text{m/s}



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